The areas of the effort and load pistons of a hydraulic press are 0.5m2 and 5m2 respectively. If a force F1 of 100N is applied on the effort piston, the force F2 on the load is
-
A.
10N -
B.
100N -
C.
500N -
D.
1000N -
E.
5000N
Correct Answer: Option D
Explanation
(frac{load}{area}) = (frac{effort}{area})
(frac{load}{5}) = (frac{100}{0.5})
load = 1000N