In the diagram, PTS is a tangent to the circle TQR at T. Calculate In the diagram, PTS is a tangent to the circle TQR at T. Calculate A. 120o B. 70o C. 60o D. 40o Correct Answer: Option B Explanation RTS = RQT (angle between a tangent and a chord at the point of contact is equal to the angle in the alternate segment) But R = Q + T = 180 RQT = 180o – (50 + 60) = 180o – 110o = 70o Since RQT = RTS = 70o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, PTS is a tangent to the circle TQR at T. Calculate

  • A.
    120o
  • B.
    70o
  • C.
    60o
  • D.
    40o
Correct Answer: Option B
Explanation

RTS = RQT (angle between a tangent and a chord at the point of contact is equal to the angle in the alternate segment) But R = Q + T = 180
RQT = 180o – (50 + 60)
= 180o – 110o
= 70o
Since RQT = RTS = 70o

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