A piano wire 0.5m long has a total mass of 0.01kg and is stretched with a tension of 800N. Calculate the frequency of the wire when it sounds its fundamental note
-
A.
200Hz -
B.
100Hz -
C.
4Hz -
D.
2Hz
Correct Answer: Option A
Explanation
F = (frac{1}{2L})(sqrtfrac {T}{m})
N:B m is mass per length
= (frac {0.01}{0.5})
= 0.02kgm-1
F = (frac{1}{2times 0.5})(sqrtfrac {800}{0.02})
= 200Hz