Water falls through a height of 50m. Determine the temperature rise at the bottom of the fall. [Neglect energy losses. Specific heat capacity of water = 4200Jkg-1 K-1, g = 10ms2]
-
A.
0.119oC -
B.
0.840oC -
C.
1.190oC -
D.
8.400oC
Correct Answer: Option A
Explanation
mgh = mc(theta)
(theta = frac{gh}{c} = frac{10 times 50}{4200})
= 0.119oC