Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?
-
A.
4.8 Vm-1 -
B.
75.0Vm-1 -
C.
4800.0Vm-1 -
D.
75000.0Vm-1
Correct Answer: Option D
Explanation
E = (frac{voltage}{distance})
= (frac{600}{8 times 10^2})
= 75000.0Vm-1