If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45…

If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3
of HCl, what is the molarity of the HCl?
  • A.
    0.094 M
  • B.
    0.150 M
  • C.
    0.940 M
  • D.
    1.500 M
Correct Answer: Option A
Explanation

NaOH + HCl → NaCl + H2O moles ratio = 1/1
↔ (MaVa) / Mb x 39.45 = 0.094

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