A black body radiates maximum energy when its surface temperature T and the corresponding wavelength (lambda)max are related by the equation (lambda)max T = constant. Given the values of the constant and surface temperature as 2.9 x 10(^{-3}) mK and 57°C respectively; Calculate the frequency of the energy radiated.
Explanation
(lambda) max = (frac{2.9 times 10^{-3}}{330}) = 8.8 x 10(^{-6})m
v = f(lambda) or f = (frac{v}{lambda})
where v = velocity of light = 3.0 x10(^{-8}) m/s
(lambda) = 8.8 x 10(^{-6})
f = (frac{v}{lambda})
= (frac{3.0 times 10^8}{8.8 times 10^{-6}})
= 3.4 x 10(^{13}) Hz