Which volume of 0.5 M H 2SO4 will exactly neutralize 20 cm 3 of 0.1 M NaOH solution?
-
A.
2.0 cm 3 -
B.
5.0 cm 3 -
C.
6.8 cm 3 -
D.
8.3 cm 3 -
E.
10.4 cm 3
Correct Answer: Option A
Explanation
(frac{C_AV_A}{C_bV_b} = frac{1}{2})
(frac{0.5 times V_A}{0.1 times 20} = frac{1}{2})
(V_A = frac{0.1 times 20}{2 times 0.5} = frac{1.0}{0.5))
= 2cm2