When the tension in a sonometer wire is doubled, the ratio of the new frequency to the initial frequency is
-
A.
(frac{1}{sqrt2}) -
B.
(frac{1}{2}) -
C.
(sqrt2) -
D.
2
Correct Answer: Option A
Explanation
(frac{F_1}{F_2}) = (sqrt{frac{T_1}{T_2}})
T2 = 2T1
(frac{F_1}{F_2}) = (sqrt{frac{T_1}{2T_1}})
(frac{F_1}{F_2}) = (sqrt2)
F(_2) : F(_1) = 1 : (sqrt{2})
(frac{F_2}{F_1} = frac{1}{sqrt{2})