What is the pH of 0.001 mol dm-3 solution of sodium hydroxide
-
A.
14 -
B.
13 -
C.
12 -
D.
11
Correct Answer: Option D
Explanation
[H+] [OH–] = 10-14[H+] = 10-14/[OH–] = 10-14/(1 * 10-3) = 10-11
pH = -Log10[H+] = – Log10[10-11] = – 1 * -11 Log10[10-11] = 1 = -1 * -11 * 1 = 11