What is the effective capacitance in the circuit?
-
A.
2(mu F) -
B.
6(mu F) -
C.
18(mu F) -
D.
216(mu F)
Correct Answer: Option A
Explanation
(frac{1}{c} = frac{1}{6} + frac{1}{6} + frac{1}{6})
= (frac{1 + 1 + 1}{6} = frac{3}{6} = frac{1}{2})
= 2(mu F)