What is drift eliminator in cooling tower

REDUCE WATER LOSS AND EMISSIONS

In all different types of cooling towers drift eliminators are used to reduce the loss of water and emissions. Above the water distribution and the cooling fills, a layer of drift eliminators is installed for this purpose.

The way this technology works is by setting obstacles in the path, in the form of “fill”, which air passes effortlessly, but water hits and gets redirected to the cooling tower walls. From there it condenses and flows downward to a reservoir, where it is harmlessly disposed of or recirculated.

Drift loss is the quantity of water loss as small water drolets from the tower top, It is made up by injectiong fresh water in the cooing water network.

The latest technology often can achieve 0.001% drift rate, down to 0.0005% drift rate depending on tower configuration. To put that into context, for 1,000 gpm (63 l/s) water flow rate, predicted drift volume is approximately 1 ounce (30 ml) per minute.

But, how can we reduce the loss volume of evaporation?” Common solution is to reduce the volume of airflow it also can help reducing cooling tower power consumption. Through decrease the rotating speed of fan and the using of variable frequency motor to reduce the volume of airflow.

Ton of Refrigeration (TR): Ton of Refrigeration (abbreviated as TR) is an important historical unit of refrigeration capacity. Originally 1 TR was defined as the rate of heat transfer required to make 1 short ton (2000 lbs) of ice per day from water at 0^oC.

A cooling tower is a heat removal device that uses water to transfer process waste heat into the atmosphere. All cooling towers, including commercial & industrial cooling towers, operate on the principle of removing heat from water by evaporating a small portion of water that is recirculated through the unit.

AIR INLET LOUVRES FOR COOLING TOWERS

Our cellular inlet louvres improve the air flow into the cooling tower. They not only hold back unwanted elements (e.g. leaves) but also prevent water splash-out which can cause icing and loss of expensive water and treatment chemicals.

Coefficient of Performance

The COP is determined by the ratio between energy usage of the compressor and the amount of useful cooling at the evaporator (for a refrigeration instalation) or useful heat extracted from the condensor (for a heat pump). A high COP value represents a high efficiency.

Rounding up 11,917 Btu/hr gives you 12,000 Btu/hr, which is one ton of air conditioner capacity. To determine how much heat must be removed to cool your home – your home’s cooling load – your HVAC contractor will follow the guidelines set forth in the ACCA’s (Air Conditioner Contractors of America) Manual J.

Divide Q (BTUs per hour) by 12,000 (the number of BTUs in one ton of cooling capacity). This yields the chiller capacity required to handle the process heat load in tons per hour: Example: 240,000/12,000= 20 tons/hr.

The terms COP (coefficient of performance) and EER (energy efficiency ratio) describe the heating and cooling efficiency of air conditioners. They indicate the ratio of heating or cooling provided by a unit relative to the amount of electrical input required to generate it.

COP is defined as the relationship between the power (kW) that is drawn out of the heat pump as cooling or heat, and the power (kW) that is supplied to the compressor. For example: A given heat pump used for air cooling has a COP = 2.

EER is defined the ratio of cooling capacity provided to electricity consumed as follows:EER=Coolingcapacity/ElectricalenergyinputThe same rating system is used for air conditioners, allowing for straightforward comparisons of different units.

Take for example a chiller which is producing 2,500kW of cooling or 8,533,364BTU/h in metric units. The electrical power demand of the chiller to produce this is 460kW. The metric calculation would be: 2,500kW / 460kW = 5.4 so the COP is 5.4.

If an air conditioner has a rating of 2.5kw, giving you 2.5kw of cooling, it is only using 0.52kw to achieve that. Then the COP of that air conditioner would be 2.5 divided by 0.525 = 4.7, essentially almost 5 times more efficient than electrical heating.

First, the basics. SEER stands for Seasonal Energy Efficiency Ratio. This is the ratio of the cooling output of an air conditioner over a typical cooling season, divided by the energy it uses in Watt-Hours. … Keep in mind that SEER ratio is a maximum efficiency rating, like the miles per gallon for your car.

‘Cooling capacity’ is the measure of an air conditioning system’s ability to remove heat from a room, thus making the room ‘cooler’. … Generally the unit used for this measurement is specified in Kilowatts (kW).