What current in amperes will deposit 2.7g of aluminium in 2 hours?
[Al = 27, F = 96 500 C mol-1]
[Al = 27, F = 96 500 C mol-1]
-
A.
32 -
B.
8 -
C.
4 -
D.
16
Correct Answer: Option C
Explanation
Al3+ + 3e → Al
3 * 96500 → 27
I = 3600 * 2 → 27
I = (2.7/27) * ((3 * 96500)/(3600 * 2))
= 4.025 ≈ 4