Two liquids, P at a temperature of 20oC and Q at a temperature of 80oC have specific heat capacities of 1.0Jkg-1oC-1 and 1.5J kg-1oC-1respectively. if equal masses of P and Q are mixed in a lagged calorimeter, then the equilibrium temperature is
-
A.
44oC -
B.
50oC -
C.
56oC -
D.
60oC -
E.
70oC
Correct Answer: Option C
Explanation
Heat lost = heat gained
m x (80 – (theta)) x 1.5 = m x ((theta) – 20) x 1
(theta) = 56oC