Two inductors of inductances 5 mll and 15 mll are connected in series and a current of 5A flows through them. the total energy stored in the inductor is
-
A.
500.0J -
B.
250.0J -
C.
62.5J -
D.
50.0J -
E.
no correct option
Correct Answer: Option E
Explanation
Total inductance,L = L1 + L2 = m
15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, (1)/2 L I2
= (1)/2 X (20)/1000 X 5-2
= 0.25 J