Two groups of male students cast their vote on a particular proposal. The results are as follows:
| In favor | Against | |
| Group A | 128 | 32 |
| Group B | 96 | 48 |
If a student is chosen at random, what is probability that he is against the proposal?
-
A.
3/19 -
B.
4/19 -
C.
5/19 -
D.
9/19 -
E.
10/19
Correct Answer: Option C
Explanation
Probability that the student is against the proposal
= (frac{32 + 48}{128 + 32 + 96 + 48})
= (frac{80}{304})
= (frac{5}{19})