Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[(frac{1}{4pi mathit{E}_o} = 9.00 times 10^9 Nm^2C{-2})]
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A.
1.44 x 10-7N -
B.
7.20 x 10-9N -
C.
7.20 x 10-11N -
D.
1.44 x 1011N
Correct Answer: Option A
Explanation
f = (frac{1}{4 pi mathit{E}_o} times frac{Q^2}{r^2} = frac{9 times 10^9(2 times 10^{-2})^2}{(0.05)^2})
= 1.44 x 10-2N