TQ is tangent to circle XYTR, TQ is tangent to circle XYTR, o, RTQ = 40o. fIND A. 108o B. 121o C. 140o D. 148o Correct Answer: Option A Explanation o (alternate segment)o(Angles in the same segments)o + 32o = 72oo(Supplementary) 72o + oo – 72o = 108o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })