Three resistors, with substances 250(Omega), 500(Omega) and 1k(Omega) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250(Omega) resistor.
-
A.
0.20V -
B.
0.86V -
C.
1.71V -
D.
3.43V
Correct Answer: Option B
Explanation
Using voltage – divider method
v1 = (frac{(R_1)}{R_T})VT
= (frac{250}{1750}) x (frac{6}{1})
= 0.86V