Three consecutive terms of a geometric progression are given as n-2, n and n+3. Find the common ratio
-
A.
1/4 -
B.
1/2 -
C.
2/3 -
D.
3/2
Correct Answer: Option D
Explanation
(r=frac{n}{n-2}hspace{1mm}andhspace{1mm}r=frac{n+3}{n}\∴frac{n}{n-2}=frac{n+3}{n}\n^2 = n^2 +3n – 2n-6\0=n-6\∴n=6\Buthspace{1mm}r = frac{n}{n-2}\r=frac{6}{6-2}\frac{6}{4}=frac{3}{2})