Three consecutive terms of a geometric progression are give as n – 2, n and n + 3. Find the common ratio
-
A.
(frac{3}{2}) -
B.
(frac{2}{3}) -
C.
(frac{1}{2}) -
D.
(frac{1}{4})
Correct Answer: Option A
Explanation
(frac{h}{n – 2} = frac{n + 3}{n})
n(^2) = (n + 3) (n – 2)
n(^2) = n(^2) + n – 6
n(^2) + n – 6 – n(^2) = 0
n – 6 = 0
n = 6
Common ratio: (frac{n}{n – 2} = frac{6}{6 – 2} = frac{6}{4}) = (frac{3}{2})
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