Three cells each of e.m.f. 1.5v and an internal resistance of 1.0(Omega) are connected in parallel across a load resistance of 2.67(Omega). Calculate the current in the load?
-
A.
0.26A -
B.
0.41A -
C.
0.50A -
D.
0.79A
Correct Answer: Option C
Explanation
E = 1.5v
rT = (frac{1 times 1times 1}{(1times1)+ (1times1) +(1times1)})
E.m. f = I(R + r) = 0.33(Omega)
1.5 = I(2.67 + 0.33)
I = 0.5A