Three capacitors each of capacitance 18(mu F) are connected in series. Calculate the effective capacitance of the capacitors
-
A.
54.00(mu F) -
B.
18.00(mu F) -
C.
6.00(mu F) -
D.
0.17(mu F)
Correct Answer: Option C
Explanation
(frac{1}{c} = frac{1}{18} + frac{1}{18} + frac{1}{18} = frac{3}{18})
c = 6(mu F)