The work done in extending a spring by 40 mm is 1.52J. Calculate the elastic constant of the spring.
-
A.
38.8 Nm-1 -
B.
60.8 Nm-1 -
C.
190.0 Nm-1 -
D.
1900.0 Nm-1 -
E.
3800.0 Nm-1
Correct Answer: Option D
Explanation
Force = Elastic constant x extension
Work done = (frac{1}{2} K times e^2)
Given Work done = 1.52J; Elastic constant (k) = ?; e = 40mm = 0.04 m
(therefore 1.52 = frac{k times (0.04)^2}{2})
(3.04 = k times 1.6 times 10^{-3})
(k = frac{3.04}{1.6} times 10^3)
= 1.9 x 10(^3)
= 1900 Nm(^{-1})