The volume of 2.5 moles of oxygen at s.t.p is
[Molar volume of a gas at s.t.p = 22.4 dm3]
[Molar volume of a gas at s.t.p = 22.4 dm3]
-
A.
50.0 dm3 -
B.
84.0 dm3 -
C.
28.0 dm3 -
D.
56.0 dm3
Correct Answer: Option D
Explanation
1 mole of gas at s.t.p = 22.4
2.5 moles → 2.5 * 22.4 = 56.00 dm3