The tendon in a man’s leg is 0.01m long. If a force of 5N stretches the tendon by 2.0 x 10-5m, calculate the strain on the muscle.
-
A.
5 x 106 -
B.
5 x 102 -
C.
2 x 10-3 -
D.
2 x 10-7
Correct Answer: Option C
Explanation
Strain = (frac{extension}{text{original length}})
(frac{2 {times} 10^{-5}}{0.01})
= 2 x 10-3