The sum of the interior angle of pentagon is 6x + 6y. Find y in terms of x.
-
A.
y = 6 – x -
B.
y = 90 – x -
C.
y = 120 – x -
D.
y = 150 – x
Correct Answer: Option B
Explanation
Sum of interior angles = (2n – 4) 90(^o)
For perntagon, n = 5
Sum of interior angles = 6 x 90(^o) = 540(^o)
6x + 6y = 540(^o)
6(x + y) = 540(^o)
x + y = (frac{540^o}{6}) = 90(^o)
y = 90(^o)
y = 90 – x
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