The solution to the simultaneous equations 3x + 5y = 4, 4x + 3y = 5 is
-
A.
((frac{-13}{11}, frac{1}{11})) -
B.
((frac{13}{11}, frac{1}{11})) -
C.
((frac{13}{11}, frac{-1}{11})) -
D.
((frac{11}{13}, frac{1}{11})) -
E.
(13, 11)
Correct Answer: Option B
Explanation
3x + 5y = 4, 4x + 3y = 5
3x + 5y = 4 x 4
4x + 3y = 5 x 3
12x + 20y = 16…..(i)
12x + 9y = 15…….(ii)
subtract eqn.(ii) from eqn.(i)
11y = 1
y = (frac{1}{11})
12x + 20 x (frac{1}{11}) = 16
12x = (frac{156}{11})
x = (frac{13}{11})
= (frac{13}{11}, frac{1}{11})