The slope of the tangent to the curve y = 3x(^2) – 2x + 5 at the point (1, 6) is
-
A.
4 -
B.
1 -
C.
6 -
D.
5
Correct Answer: Option A
Explanation
y = 3x(^2) – 2x + 5
Slope = (frac{mathrm d y}{mathrm d x} = 6x – 2)
At x = 1,
Slope : 6(1) – 2 = 4.
The slope of the tangent to the curve y = 3x(^2) – 2x + 5 at the point (1, 6) is
y = 3x(^2) – 2x + 5
Slope = (frac{mathrm d y}{mathrm d x} = 6x – 2)
At x = 1,
Slope : 6(1) – 2 = 4.