the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration given that the speed of sound in air is 340m-1
-
A.
1360Hz -
B.
694Hz -
C.
680Hz -
D.
34Hz -
E.
340Hz
Correct Answer: Option C
Explanation
f = (frac{v}{2(l_2 – l_1)} = frac{340}{2(0.37 – 0.12)} = frac{34}{0.5}) = 680