The pOH of a solution of 0.25 mol dm-3 of hydrochloric acid is
-
A.
12.40 -
B.
13.40 -
C.
14.40 -
D.
14.60
Correct Answer: Option B
Explanation
pOH = -log [2.5 * 10-1] = -log[-0.3979 + 1] = 13.40
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