The percentage composition of a hydrocarbon is 79.2 carbon 20.8 hydrogen. Calculate its empirical formula [H = 1, C = 12]
-
A.
CH -
B.
CH3 -
C.
CH4 -
D.
C2H2 -
E.
C2H6
Correct Answer: Option B
Explanation
Relative No of Moles for Carbon = 79.2% ÷ 12 = 6.6
Relative No of Moles for Hydrogen = 20.8% ÷ 1 = 20.8
Ratio of Moles = Carbon 6.6 ÷ 6.6 = 1 Hydrogen = 20.8 ÷ 6.6 ~ 3
EMPIRICAL FORMULA IS CH(_3)