The oxidation state(s) of nitrogen in ammonium nitrite is/are
-
A.
-3, +3 -
B.
+5 -
C.
-3, +5 -
D.
-3
Correct Answer: Option A
Explanation
Ammonium nitrite = NH(_4)NO(_2)
NH(_4 ^+): Let the oxidation number of Nitrogen = x
x + 4 = 1 (implies) x = 1 – 4
x = -3
NO(_2 ^-): x – 4 = -1
x = -1 + 4 (implies) x = +3.
The oxidation numbers for Nitrogen in Ammonium Nitrite = -3, +3.
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