The oxidation state of oxygen in tetraoxosulphate (VI) acid is
-
A.
-4 -
B.
-2 -
C.
+4 -
D.
-8
Correct Answer: Option B
Explanation
H2SO4
(O.N of hydrogen * 2 ) + O.N of sulphur + O.N of oxygen * 4 = 0
∴ 1 * 2 + 6 + 4x = 0
2 + 6 + 4x = 0
8 + 4x = 0
4x 0 – 8 = -8
4x = -8x = -8/4 = -2