The oxidation number of iodine in the iodate ion (IO –3) is
-
A.
-5 -
B.
-1 -
C.
+1 -
D.
+5
Correct Answer: Option D
Explanation
1O3
[oxidation number of 1] + [oxidation number of 0] x 3 = -1
x + -2 x 3 = 1
x – 6 = – 1
x = – 1 + 6 = +5
1O3
[oxidation number of 1] + [oxidation number of 0] x 3 = -1
x + -2 x 3 = 1
x – 6 = – 1
x = – 1 + 6 = +5