The number of sulphur atoms in 3.20g of SO(_{2(g)}) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10(^{23})]
-
A.
3.01 x 1022 -
B.
6.02 x 1022 -
C.
6.02 x1023 -
D.
1.20 x 1024
Correct Answer: Option B
Explanation
32g of sulphur = 6.02 x 10(^{23}) atoms
3.2g of sulphur = x ,
x = (frac{3.2 times 6.02 times 10^{23}}{32}) = 0.602 x 10(^{23}) = 6.02 x 10(^{22}) atom