The number of oxygen molecules present in 16.0g of the gas is ______? [Avogadro’s number…

The number of oxygen molecules present in 16.0g of the gas is ______?
[Avogadro’s number = 6.02 x 1023]
  • A.
    6.02 x 1022
  • B.
    6.02 x 1023
  • C.
    3.01 x 1023
  • D.
    1.51 x 1023
Correct Answer: Option C
Explanation

1 mole = Molar mass of gas = Avogadros number
32g of O2 = 6.02 x 1023
16g of O2 = x
x = (frac{16 times 6.02 times 10^23}{32}) = 3.01 x 1023

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