The nth term of a sequence is given by 3.2(^{n-2}). Write down the first three terms of the sequence.
-
A.
2/3, 0, 6 -
B.
3/2, 3, 6, -
C.
2/3, 3, 8/3 -
D.
2/3, 3/4, 6 -
E.
2/3, 3, 1/3
Correct Answer: Option B
Explanation
(T_n = 3. 2^{n – 2} \
T_{1} = 3. 2^{1 – 2} = 3. 2^{-1} \
T_1 = frac{3}{2} )
(T_2 = 3. 2^{2 – 2} \
T_2 = 3. 2^0 = 3)
(T_3 = 3. 2^{3 – 2} = 3. 2^1 \
T_3 = 6)
The first 3 terms of the sequence are (frac{3}{2}), 3 and 6.