The nth term of a sequence is given by 2(^{2n – 1}). Find the sum of the first four terms.
-
A.
74 -
B.
32 -
C.
42 -
D.
170
Correct Answer: Option D
Explanation
(T_n = 2^{2n – 1})
(T_1 = 2^{2(1) – 1} )
= 2
(T_2 = 2^{2(2) – 1})
= 8
(T_3 = 2^{2(3) – 1})
= 32
(T_4 = 2^{2(4) – 1})
= 128
(T_1 + T_2 + T_3 + T_4 = 2 + 8 + 32 + 128)
= 170
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