The net capacitance in the circuit above is

Correct Answer: Option D

Explanation

For capacitance i n parallel, 2µF and 2µF are in parallel,
their equivalence is 2µF and 2µF = 4µF
The 4µF generated is now in series with the remaining 4µF.
The net capacitance for series connection is
(frac{1}{C}) = (frac{1}{4}) + (frac{1}{4}) = 1 + (frac{1}{4}) = (frac{2}{4})
C = (frac{4}{2})
= 2µF

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