The minimum point on the curve y = x2 – 6x + 5 is at
-
A.
(1, 5) -
B.
(2, 3) -
C.
(-3, -4) -
D.
(3, -4)
Correct Answer: Option D
Explanation
Given the curve (y = x^{2} – 6x + 5)
At minimum or maximum point, (frac{mathrm d y}{mathrm d x} = 0)
(frac{mathrm d y}{mathrm d x} = 2x – 6)
(2x – 6 = 0 implies x = 3)
Since 3 > 0, it is a minimum point.
When x = 3, (y = 3^{2} – 6(3) + 5 = -4)
Hence, the turning point has coordinates (3, -4).