The mass of silver deposited when a current of 10a is passed through a solution…

The mass of silver deposited when a current of 10a is passed through a solution of silver salt for 4830s is
[Ag = 108, F = 96500 c mol-1]
  • A.
    108.0g
  • B.
    54.0g
  • C.
    27.0g
  • D.
    13.5gq
Correct Answer: Option B
Explanation

Ag + ie → Ag+
If w 96500 C deposit 108g of silver
∴ 10 * 4830 will deposit (10 * 4830 * 108)/96500
= 5216400/96500 = 54.06g

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