The horizontal component of the initial speed of a particle projected at 30° to the horizontal is 50 m(^{-1}). If the acceleration of free fall due to gravity is 10 ms(^{-2}), determine its;
(a) initial speed;
(b) speed at the maximum height reached.
Explanation
(a) Horizontal component
(U_x = U cos theta)
U = (frac{U_x}{cos0} = frac{50}{cos 30^o}) = 57.7 m/s
(b) At maximum height
(v_y = O) and (V_x = U_x) = 50m/s
V = (sqrt{V^2_x + V^2_v} = sqrt{50^2 + 0^2})
= 50m/s