The hatch door of a submarine has an area of 0.5m2. The specific gravity of sea water is 1.03. Assume that g = 10ms-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is
-
A.
1.03 x 105N -
B.
1.03 x 104Nm-2 -
C.
1.06 x 105Nm-2 -
D.
2.06 x 106N -
E.
1.03 x 103N
Correct Answer: Option E
Explanation
Pressure in liquid = e x h x g
Pressure in solid = (frac{force}{area})
(frac{force}{area}) = e x h x g
force = 0.5 x 10 x 200 x 1.03
= 1030N