The ground stated energy for the hydrogen atom is 5.44 x 10-19J . If an electron drops from zero energy to ground state, calculate the frequency of the emitted radiation.
[h = 6.6 x 10-34 Js]
[h = 6.6 x 10-34 Js]
-
A.
5.0 x 1016 Hz -
B.
2.0 x 1016 Hz -
C.
5.0 x 1015 Hz -
D.
2.0 x 1015 Hz -
E.
No correct option
Correct Answer: Option E
Explanation
∆E = hf
f = (∆E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014