The equation of the line through the points (4,2) and (-8, -2) is 3y = px + q, where p and q are constants. Find the value of p.
-
A.
1 -
B.
2 -
C.
3 -
D.
9
Correct Answer: Option A
Explanation
Using the two – point from
(frac{y – y_1}{y_2 – y_1} = frac{x – x_1}{x_2 – x_1})
(frac{y – 2}{-2 – 2} = frac{x – 4}{-8 – 4})
(frac{y – 2}{-4} = frac{x – 4}{-12})
(frac{-12(y -2)}{-4}) = x – 4
3(y -2) = x -4
3y – 6 = x – 4
3y = x – 4 + 6
3y = x + 2…
By comparing the equations;
3y = px + , p = 1