The equation of a circle is (x^{2} + y^{2} – 8x + 9y + 15…

The equation of a circle is (x^{2} + y^{2} – 8x + 9y + 15 = 0). Find its radius.

  • A.
    5
  • B.
    (frac{1}{2}sqrt{15})
  • C.
    (frac{1}{2}sqrt{85})
  • D.
    (sqrt{85})
Correct Answer: Option C
Explanation

The equation of a circle is given as ((x – a)^{2} + (y – b)^{2} = r^{2}).

Expanding, we have: (x^{2} – 2ax + a^{2} + y^{2} – 2by + b^{2} = r^{2})

(x^{2} + y^{2} – 2ax – 2by + a^{2} + b^{2} = r^{2})

Comparing with the equation, (x^{2} + y^{2} – 8x + 9y = -15), we have

(2a = 8; 2b = -9; r^{2} – a^{2} – b^{2} = -15)

(a = 4; b = frac{-9}{2})

(therefore  r^{2} = -15 + 4^{2} + (frac{-9}{2})^{2})

= (-15 + 16 + frac{81}{4} = frac{85}{4})

(r = sqrt{frac{85}{4} = frac{1}{2}sqrt{85})

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