The energy contained in a wire when it extended by 0.02m by a force 500 N is
-
A.
5J -
B.
10J -
C.
103J -
D.
104
Correct Answer: Option A
Explanation
Energy = (frac{1}{2})Fe
= (frac{1}{2}) x 500 x 0.02
E = 5J
Energy = (frac{1}{2})Fe
= (frac{1}{2}) x 500 x 0.02
E = 5J