The empirical formula of a compound containing 0.067mol Cu and 0.066mol O is [Cu = 63.5, O = 16]
-
A.
(Cu_{2}O) -
B.
(CuO) -
C.
(CuO_{2}) -
D.
(CuO_{4})
Correct Answer: Option B
Explanation
Cu : O
0.067 : 0.066
mole ratio (frac{0.067}{0.066}) : (frac{0.066}{0.066})
= 1 : 1
= CuO