The distance between two successive trough of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave
-
A.
165.0 ms-1 -
B.
330.0ms-1 -
C.
41.5ms-1 -
D.
85.0ms-1
Correct Answer: Option B
Explanation
v = f(lambda)
= 825 x 0.4
= 330.0ms-1